A 6.55 g sample of aniline
(C6H5NH2, molar mass = 93.13
g/mol) was combusted in a bomb calorimeter. If the temperature rose
by 32.9°C, use the information below to determine the heat capacity
of the calorimeter.
4 C6H5NH2(l) + 35 O2(g)
→ 24 CO2(g) + 14 H2O(g) + 4
NO2(g)
ΔH°rxn = -1.28 x 104 kJ
4 C6H5NH2(l) + 35
O2(g) → 24 CO2(g) + 14 H2O(g) + 4
NO2(g)
ΔH°rxn = -1.28 x 104 kJ
First calculate the number of moles of aniline as follows:
(6.55 g C6H5NH2) / (93.13 g C6H5NH2/mol)= 0.070 mol
Now calculate the total ΔH°rxn as follows:
1.28 x 104 kJ/ 4 mol C6H5NH2 * 0.07033 mol = 225.056 kJ
the heat capacity of the calorimeter = total amount of heat /
temperature change
(225.056 kJ) / (32.9 °C) = 6.84 kJ/°C
A 6.55 g sample of aniline (C6H5NH2, molar mass = 93.13 g/mol) was combusted in a bomb calorimeter. If the temperature...
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