Ammonia gas and oxygen gas react to form water vapor and nitrogen monoxide gas. What volume of water would be produced by this reaction if 7.41m3 of oxygen were consumed? Also, be sure your answer has a unit symbol, and is rounded to 3 significant digits.
Balanced chemical equation is:
4 NH3 + 5 O2 -> 6 H2O + 4 NO
From reaction,
volume of H2O required = (6/5)*volume of O2
= (6/5)*7.41 m^3
= 8.89 m^3
Answer: 8.89 m^3
Ammonia gas and oxygen gas react to form water vapor and nitrogen monoxide gas. What volume...
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