Question

In order to analyze water samples using a spectrophotometer or plate reader, it is necessary to turn the molecules of nitrate into a dye molecule that can be quantified. The first step in turning nitrate (NO₃^-)  into a dye molecule is reducing it to a molecule of nitrite (NO₂^-). This is done by reacting the NO₃^- with cadmium.

After the reduction reaction, the NO₂^- is reacted with two additional reagents. The first reagent, Reagent A, is a solution of sulfanilamide and hydrochloric acid. The second reagent, Reagent B, is a solution of N-(1-naphthyl)-ethylenediamine, called NNED for short. The compounds are mixed with the water sample and produce a purple color. The intensity of the purple color is directly related to the concentration of nitrite in the water sample. We can measure how purple the water turns as absorbance on a spectrophotometer and then convert the absorbance to concentration of nitrate.

To make Reagent A, we will need to make a solution of 10.0 g of sulfanilamide in 1 L of 2.4 molar hydrochloric acid (HCl).

The stock solution of HCl is 6 molar HCl. How many milliliters (mL) of 12 M HCl would you add to produce 0.15 liters (L) of HCl? _________ mL HCl

After creating 0.15 L of 2.4 molar HCl solution, how many grams of sulfanilamide will be added? ______________ g sulfanilamide

Answer 1

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