Question

a) If we assume the population mean is 98.60 and the standard deviation is 0.6, what...

a) If we assume the population mean is 98.60 and the standard deviation is 0.6, what is the probability of a single person having a temperature of 98.25 or less? (Round to four decimal places.

This should be the theoretical probability that is calculated, NOT the empirical probability from the simulation.)

b) If we assume the population mean is 98.60 and the standard deviation is 0.6, what is the probability of obtaining a sample mean of 98.25 or less from a sample of 112 individuals?

(Round to six (6) decimal places.This should be the theoretical probability that is calculated, NOT the empirical probability from the simulation.)

c) What can we say about the assumption that the population mean is 98.60? Explain your answer completely.

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Answer #1

Hello SIr/ Mam

(a)

Given that:

Mean = 98.60
Standard Deviation = 0.60
X 98.25

(b)

New S.D. = 0.6/(112^0.5) = 0.0567

Hence,

Mean = 98.60
Standard Deviation = 0.06
X 98.25

I hope this solves your doubt.

Feel free to comment if you still have any query or need something else. I'll help asap.

Do give a thumbs up if you find this helpful.

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