Consider events A and B such that P(A)=0.3,P(B|A)=0.9,P(B|A¯¯¯)=0.4. Calculate P(A|B¯¯). Give your answer as a fraction in its simplest form.
Consider events A and B such that P(A)=0.3,P(B|A)=0.9,P(B|A¯¯¯)=0.4. Calculate P(A|B¯¯). Give your answer as a fraction...
If A and B are independent events with P(A)=0.3 and P(B)=0.9, find P(A AND B). Provide your answer below:
For two events, A and B, P(A) = 0.4 and P(B) = 0.3 (a) If A and B are independent, find ?(? ∩ ?), ?(?|?), ?(? ∪ ?). (b) If A and B are dependent with ?(?|?) = 0.6, find ?(? ∪ ?),?(?|?).
For two events, A and B, P(A) = 0.4 and P(B) = 0.3 (a) If A and B are independent, find ?(? ∩ ?), ?(?|?), ?(? ∪ ?). (b) If A and B are dependent with ?(?|?) = 0.6, find ?(? ∪ ?),?(?|?).
For two events, M and N, P(M)= 0.4, P(NİM) = 0.3, and P(NIM") = 0.6. Find P(M"\N"). P(M'\N') = (Simplify your answer. Type an integer or a fraction.)
Two events A and B are such that P(A) = 0.4, P(B) = 0.5, and P(AUB) = 0.7. (a) Find P(A n B). 0.2 (b) Find P(AUB). 0.8 (c) Find P(An B). 0.3 (d) Find P(AB). (Enter your probability as a fraction.) 1/2
= 0.3. Consider events A and B such that P(A) = 0.7, P(B) = 0.2 and P(ANB) Compute the probability that A will occur, given that B does not occur, A. 0.4 B. 0.1 C. -0.1 D. 0.5 E. none of the preceding
Consider two events A and B. It is known that P(A) = 0.3, P(B|A) -0.2 and Calculate the following. Enter your answers to at least four decimal places accuracy. P(B|AC) = 0.3. (a) P(AC) - $ (b) P(B) - (c) P(ANB) (d) P(AB) = 3
1. If P(A) = 0.4, P(B) = 0.6, P(C) = 0.3, P = 0.24, P = 0.15 and P(A U C) = 0.82. Which of the events A, B and C are independent? Give reasons for your answers. (A B) We were unable to transcribe this image
Tesponse. Question 6 Let A and B be two events, such that P(A)=0.6, P(B)=0.4 and P((not A) and (not B))=0.2. (6 Please give your answer as simplified fraction or decimal number (e.g. 3/4 or 0.75) a) Find P(A or B)= 0.76 b) Find P((not A) and (B))= || I c) Find P( AB)=
For two events A and B, P(A)=0.4 and P(B)=0.3 (a) If A and B are independent, then P(A|B)= P(A∪B)= P(A∩B)= (b) If A and B are dependent and P(A|B)=0.6, then P(A∩B)= P(B|A) = 2. All that is left in a packet of candy are 8 reds, 2 greens, and 3 blues. (a)What is the probability that a random drawing yields a green followed by a blue assuming that the first candy drawn is put back into the packet?