Question

Using Java; Consider the following text file format.

Ruminant
Shaman
30
Elentriel
Shaman
70
Aelkine
Druid
29
Barbatus
Druid
70
Ukaimar
Mage
47
Mariko
Priest
33
Farmbuyer
Priest
70
Valefar
Warlock
42
Teslar
Paladin
64
Nerdsbane
Hunter
12

We wish to store information regarding several characters in a video game. Each character has a name, and a class, and a level. This information is repeated, 3 lines per character, for any number of characters. To simplify processing, the very first line of the file will be an integer that provides the number of characters stored in the file. Note that this number represents the number of records, not the number of lines (each record consists of one name, one class, and one level, i.e. three lines in the file).   

Write a program that opens the file shown above and reads in the contents. Use 3 separate arrays to hold the character names (String), classes (String), and levels (int). Once you have read in the entire file, print the information to the screen in the following format.

DESIRED OUTPUT:

Name           Class          Level

Ruminant       Shaman         30

Elentriel      Shaman         70

Aelkine        Druid          29

Barbatus       Druid          70

Ukaimar        Mage           47

Mariko         Priest         33

Farmbuyer      Priest         70

Valefar        Warlock        42

Teslar         Paladin        64

Nerdsbane      Hunter         12

Here is my code so far; however I am unsure how to read in and allocate the strings with each other and then to the respective level so all i have is reading in the character level and allocating that to an array.

public static void main(String[] args) throws FileNotFoundException {
  
int [] charLevel;
String [] charName;
String [] charClass;

try {
//read in levels(integer values) of the characters from the file
Scanner level = new Scanner(new File("character.txt"));

int count = 0;
while(level.hasNextLine()) {
level.nextLine();
count++;
}
level.close();

//assign levels to an array
charLevel = new int[count];
level = new Scanner(new File("character.txt"));
//declare scanner to read levels from start of file
for (int i=0; i<count; i++) {
//add each level from the file to the array charLevel
charLevel[i] = level.nextInt();
}
level.close();
  
} catch (FileNotFoundException e) {
e.printStackTrace();
System.err.println("Unable to open file!");
  
}
}

Answer 1

SOURCE CODE IN JAVA:

import java.util.Scanner;
import java.io.File;
class Characters
{
public static void main(String args[])
{
try
{
Scanner in=new Scanner(new File("character.txt")); //opening the file
int n=in.nextInt(); //reading number of characters to be read from file
//creating arrays of the size read
String names[]=new String[n];
String classes[]=new String[n];
int levels[]=new int[n];
//reading the different characters into the arrays
for(int i=0;i<n;i++)
{
names[i]=in.next();
classes[i]=in.next();
levels[i]=in.nextInt();
}
in.close();
//output
System.out.println("Name Class Level");
for(int i=0;i<n;i++)
System.out.printf("%-10s %-10s %d\n",names[i],classes[i],levels[i]);
  
}
catch(Exception e)
{
System.out.println(e);
}
}
}

OUTPUT: