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Consider the evaporation of methanol at 25.0∘C: CH3OH(l)→CH3OH(g). 1. Find ΔG∘ at 25.0∘C. 2. PCH3OH=160.0 mmHg...

Consider the evaporation of methanol at 25.0∘C:

CH3OH(l)→CH3OH(g).

1. Find ΔG∘ at 25.0∘C.

2. PCH3OH=160.0 mmHg

3.PCH3OH=104.0 mmHg

4. PCH3OH=11.00 mmHg

5. The vapor pressure of methanol is 143 mmHg. Identify the best reason to explain why methanol spontaneously evaporates in open air at 25.0∘C and standard pressure (760 mmHg).

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