Consider the evaporation of methanol at 25.0 ?C:
CH3OH(l)?CH3OH(g).
A. Find ?G? at 25.0 ?C.
B. Find ?G at 25.0 ?C under the following nonstandard
conditions:
(i)PCH3OH= 156.0mmHg .
C. Find ?G at 25.0 ?C under the following nonstandard
conditions:
(ii) PCH3OH= 106.0mmHg .
D. Find ?G at 25.0 ?C under the following nonstandard
conditions:
(iii) PCH3OH= 13.0mmHg .
Consider the evaporation of methanol at 25.0 ?C: CH3OH(l)?CH3OH(g). A. Find ?G? at 25.0 ?C. B....
Consider the evaporation of methanol at 25.0∘C: CH3OH(l)→CH3OH(g). 1. Find ΔG∘ at 25.0∘C. 2. PCH3OH=160.0 mmHg 3.PCH3OH=104.0 mmHg 4. PCH3OH=11.00 mmHg 5. The vapor pressure of methanol is 143 mmHg. Identify the best reason to explain why methanol spontaneously evaporates in open air at 25.0∘C and standard pressure (760 mmHg).
73. Consider the reaction: CO(g) + 2H2(g) <--> CH3OH(g) Kp= 2.26X10E4 at 25 C Calculate ΔGorxnfor the reaction at 25C under each of the following conditions: a. standard conditions b. at equilibrium c. PCH3OH= 1.0 atm; PCO= PH2 = 0.010 atm
Consider the following reaction: CH3OH(g)⇌CO(g)+2H2(g) Calculate ΔG for this reaction at 25 ∘C under the following conditions: PCH3OH= 0.840 atm PCO= 0.130 atm PH2= 0.175 atm
Consider the following reaction: CH3OH(g)⇌CO(g)+2H2(g) Calculate ΔG for this reaction at 25 ∘C under the following conditions: PCH3OH= 0.835 atm PCO= 0.135 atm PH2= 0.165 atm
Consider the following reaction: CO(g)+2H2(g)⇌CH3OH(g) Kp=2.26×104 at 25 ∘C. Calculate ΔGrxn for the reaction at 25 ∘C under each of the following conditions. Part A: standard conditions Part B: at equalibrium Part C: PCH3OH= 1.5 atm ; PCO=PH2= 1.4×10−2 atm
1) Consider the equilibrium of methanol vapor and the liquid. CH3OH(l)↽−−⇀CH3OH(g) Thermodynamic Table at 25 ∘C Substance ΔHf∘ (kJ/mol) S∘ (J/mol‑K) ΔGf∘ (kJ/mol) CH3OH(l) −239.2 126.8 −166.6 CH3OH(g) −201.0 239.9 −162.3 What is the vapor pressure of the methanol at −30 ∘C? Pvap= atm What is the vapor pressure of the methanol at 40 ∘C? Pvap= 2) Substance ΔG°f(kJ/mol) M2O(s) −8.70 M(s) 0 O2(g) 0 Consider the decomposition of a metal oxide to its elements, where M represents a generic...
M12. Methanol, CH3OH, has been considered as a possible fuel. Consider its oxidation: 2 CH3OH(1) + 3 O2(g) → 2 CO2(g) + 4H2O(g) AGºrx = -1372 kJ/mol What is the maximum work that can be obtained by oxidizing 0.50 mol of methanol under standard conditions?
Methanol, CH3OH (l), combusts according to the following equation: 2 CH3OH (l) + 3 O2 (g) → 2 CO2 (g) + 4 H2O (l) ∆rHo (298 K) = −1452 kJ Here is a list of Entropies of formation: S (J K-1 mol-1) at 298 K CH3OH (l) =126.8 O2 (g) = 205.14 CO2 (g) = 213.74 H2O = (l) 69.91 (a) If the above reaction was used in a fuel cell, say, to perform work, what will be the maximum...
Methanol (CH3OH) burns according to the equation 2CH3OH(l) + 3O2(g) → 2CO2(g) + 4H2O(l), ΔH°rxn = –1454 kJ/mol. A) How much heat, in kilojoules, is given off when 150.0 g of methanol is burned? [ Select ] B) How many grams of CO2 are produced when the amount of heat determined in part A is released? [ Select ] Molar masses: CH3OH = 32.04 g/mol O2 = 32.00 g/mol CO2 = 44.01 g/mol H2O = 18.02 g/mol
From the following heats of combustion, CH3OH(l) + 3/2O2(g) → CO2(g) + 2H2O(l) ΔHorxn = –726.4 kJ/mol C(graphite) + O2(g) → CO2(g) ΔHorxn = –393.5 kJ/mol H2(g) + ½O2(g) → H2O(l) ΔHorxn = –285.8 kJ/mol Calculate the enthalpy of formation of methanol (CH3OH) from its elements. C(graphite) + 2H2(g) + ½O2(g) → CH3OH(l) Methanol (CH3OH) is an organic solvent and is also used as a fuel in some automobile engines. From...