In the lower bound proof for sorting, why does a sorted input require fewer comparisons than...
In the lower bound proof for sorting, why does a sorted input
require fewer comparisons than an
unsorted one? (Hint: think about how much you 'learn' from each
comparison in both of those
cases.)[2 points]
Homework Answers
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In the lower bound proof for sorting, why dos a sorted input require fewere comparisons than an unsorted one?(Hint: think about how much you 'learn' from each comparison in both those cases)
SOL::-
--> In sorting when all elements are sorted and comparisions are made minimum(which means less permutation required in sorting)
--> so it is counted as a best case and time complexity of best case of any sorting algorithm is minimum and if take case of unsorted algorithm
--> we required more permutation to arrange all items in sorted format and it comes under worst case complexity and it is higher.
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