We have previously described Newton's second law as ΣF = ma but we now also see that in terms of momentum we can state Newton's second law as:
a. Σp = F/v
b. Σp = ma
. Σm = pa
d. ΣF = dp/dt
We have previously described Newton's second law as ΣF = ma but we now also see...
Apply the momentum form of Newton's second law, F = dp/dt, to the relativistic momentum formula. Take the derivative and explain how the result is not necessarily equivalent to F=ma.
i did the lab today n have 2 questions. 1. Newton's original law was written in term of momentum and time. Show how than can be rearranged to what we know as Newton's second law of motion F=ma 2. What circumstances would lead to a situation where linear momentum is not conserved ?
Can you please give me the whole solution for this question! Thanks 2. According to Newton's Law of Universal Gravitation, the gravitational force on an object of mass m that has been projected vertically upward from Earth's surface is F( is the objer s distan boe he urfac at time t, Ris Earth's radius, ngR (x+R)2 and g is the acceleration due to gravity. Also, by Newton's Second law, mgR2 (x +R)2 dv F = mal = m dt =...
1) Up until now we have always ignored air resistance. We should now add it. Let us just think of simple 1-dimensional problem, dropping a ball of mass m from a height H but with air resistance. We can model the air resistance as a force proportional to the velocity, fair = bu. The coefficient b is a constant. (For this problem you can use calculus textbooks or wolfram alpha to do the calculus.) • What are the units on...
please explain the answer 1) Up until now we have always ignored air resistance. We should now add it. Let us just think of simple 1-dimensional problem, dropping a ball of mass m from a height H but 2 with air resistance. We can model the air resistance as a force proportional to the velocity, fair = bv. The coefficient bis a constant. (For this problem you can use calculus textbooks or wolfram alpha to do the calculus.) What are...
please explain the answer. 1) Up until now we have always ignored air resistance. We should now add it. Let us just think of simple 1-dimensional problem, dropping a ball of mass m from a height H but 2 with air resistance. We can model the air resistance as a force proportional to the velocity, fair = bv. The coefficient bis a constant. (For this problem you can use calculus textbooks or wolfram alpha to do the calculus.) What are...
Static Equlibrium: The principle of static equilibrium is based on Newton's Second Law of Motion in the linear (translational) and rotational dimensions. The Second Law in these dimensions are: ∑?_?=0 ∑?_?=0 ∑?=0 where τ = rFsinθ is the torque. When all of these conditions are true, we have achieved static equilibrium. Below is a picture of a rod, suspended by a rope. On either end is an object which exerts a torque on the rod about the pivot point (the...
A) Using Newton's second law, write equations for ax and ay, where a⃗ =axi^+ayj^ is the acceleration of the particle. Express your answer in terms of the variables q, B, vx, vy, and m. Enter your answers separated by a comma. B) Differentiate the second of these equations with respect to time. Then substitute your expression for ax=dvx/dt to determine an equation for dv2y/dt2 in terms of vy. Express your answer in terms of the variables q, B, vy, and...
Review Select the correct equation for Newton's second law for the mass before the launch and during takeoff. View Available Hint(s) Just before launching from earth, an astronaut ties a small mass m to the ceiling of his cockpit using a string of length L and mass per unit length . The mass of the string is significantly smaller than the mass of the tied object. He then plucks the string and measures the frequency of its n 1 and...
6. (10 points Extra Credit) Electrodynamics is not the only subject that utilizes Gauss' Law. We can also use it to study Newtonian gravity. The acceleration due to gravity (9can be written as, where G is Newton's gravitational constant and ρ is the m ass density. This leads us to the usual formulation of Newton's universal law of gravity,或刃--GM(f/r, as expected (if we assume V xğ-0). This "irrotational" condition allows us write (in analogy to the electric field), --Vo and...