You measure 24 textbooks' weights, and find they have a mean weight of 47 ounces. Assume the population standard deviation is 3.6 ounces. Based on this, construct a 95% confidence interval for the true population mean textbook weight. Give your answers as decimals, to two places
Solution
Given that,
= 47
= 3.6
n = 24
A ) At 95% confidence level the z is ,
= 1 - 95% = 1 - 0.95 = 0.05
/ 2 = 0.05 / 2 = 0.025
Z/2 = Z0.025 = 1.960
Margin of error = E = Z/2* (/n)
= 1.960 * (3.6 / 24 )
= 1.44
At 95% confidence interval estimate of the population mean is,
- E < < + E
47 - 1.44 < < 47 + 1.44
45.56< < 48.44
(45.56 , 48.44 )
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