An 1700 WW arc welder is connected to a 660−Vrms660−Vrms ac line.
Calculate the peak current.
An 1700 WW arc welder is connected to a 660−Vrms660−Vrms ac line. Calculate the peak current.
An 2000 WW arc welder is connected to a 660−Vrms660−Vrms ac line. Peak voltage is 930v Calculate the peak current. Second question: Two resistors when connected in series to a 120-VV line use one-fourth the power that is used when they are connected in parallel. If one resistor is 2.1 kΩkΩ , what is the resistance of the other?
Constants An 2300 W arc welder is connected to a 660-Vrms ac line. Part A Calculate the peak voltage. Express your answer using two significant figures. 000 ΑΣΦ Vpeak Submit Request Answer Part B Calculate the peak current. Express your answer using two significant figures. 0 ΑΣΦ Ipeak Submit Request Answer
An 1600 W arc welder is connected to a 660-V_rms ac line. Calculate the peak voltage. Express your answer using two significant figures. Calculate the peak current. Express your answer using two significant figures.
An 1800 W arc welder is connected to a 660 V rms ac line. Calculate (a) the peak voltage, (b) the peak current, and (c) the resistance of the welder. Show all work. Thank you! P.S-Don
What voltage will produce 0.35 A of current through a 4800-Ω resistor? A 9.0-V battery is connected to a bulb whose resistance is 2.2 Ω How many electrons leave the battery per minute? What is the resistance of a 7.4-m length of copper wire 1.4 mm in diameter? The resistivity of copper is 1.68×10−8Ω⋅m A 12-V battery causes a current of 0.72 A through a resistor. What is its resistance? How many joules of energy does the battery lose in...
Chapter 31, Problem 053 An air conditioner connected to a 120 Vrms ac line is equivalent to a 15.2 2 resistance and a 1.23 inductive reactance in series. Calculate (a) the impedance of the air conditioner and (b) the average rate at which energy is supplied to the appliance. (a) Number Units (b) Number Units
Calculate the peak current in a 3.0?k? resistor connected to a 220-V rms ac source. Ipeak= _________A
Calculate the peak current in a 2.5 -k ohm resistor connected to a 220-V rms ac source. Express your answer using two significant figures. I_peak =
The peak current through an inductor is 12.0 mA when connected to an AC source with a peak voltage of 1.0 V . What is the inductive reactance of the inductor?
An ac generator supplies an rms (not peak) voltage of 180 V at 60.0 Hz. The generator is connected in series with a 0.50-H inductor, a 6.0-1F capacitor, and a 300-ohm resistor. What is the peak (not rms) current through the resistor? Vrms=2 Ime (R? +(X2 – Xc)”), Xı = 26 fL, X. : 9 2fC