Question

What voltage will produce 0.35 A of current through a 4800-Ω resistor?

A 9.0-V battery is connected to a bulb whose resistance is 2.2 Ω

How many electrons leave the battery per minute?

What is the resistance of a 7.4-m length of copper wire 1.4 mm in diameter? The resistivity of copper is 1.68×10−8Ω⋅m

A 12-V battery causes a current of 0.72 A through a resistor.

What is its resistance?

How many joules of energy does the battery lose in a minute?

An 1500 W arc welder is connected to a 660−Vrms ac line

Calculate the peak voltage

Calculate the peak current.

Answer 1

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Thevoltage is (0.35)(4800) 1680 V The current through bulb is 9 2.2 4.1 A Therefore, number ofelectrons is, ne It n- (4.1 A (60 s) 1.6x10-19 c -1.5x1021 electrons The resistance of the copper wire is, (1.7x10* m)(7.4 m) x(1.4x10-3 m) 0.02 Ω The resistance is 12 0.72 16.7 Ω The energy loss is, (0.72)-(16.7 Ω)(60s) 519 J