A normal distribution has a mean of 99 and a standard deviation of 10. Find the probability that a value selected at random is in the following interval. at most 109
Solution :
Given that ,
mean = = 99
standard deviation = = 10
P(x 109)
= P[(x - ) / (109 - 99) / 10]
= P(z 1)
= 0.8413
Probability = 0.8413
A normal distribution has a mean of 99 and a standard deviation of 10. Find the...
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