here,
the potential difference , V = 146 V
the surface charge density , sigma = Q /A
sigma = ( C * V )/A
sigma = ( A * e0 * V /d) /A
2.3 * 10^-10 = 8.85 * 10^-12 * 146 /d
d = 5.62 m
the seperation between the plates is 5.62 m
The 24 consonant sounds comprise six stops (plosives): p, b, t, d, k, g; the fricatives f, v, θ (as in thin), ð [eth] (as in then), s, z, ∫ [esh] (as in ship), Ʒ (as in pleasure), and h; two affricatives: t∫ (as in church) and dƷ (as the j in jam); the nasals m, n, ŋ (the sound that occurs at the end of words such as young); the lateral l; the postalveolar or retroflex r; and the semivowels j (often spelled y) and w. These remain fairly stable, but Inland Northern American differs from RP in two respects: (1) r following vowels is preserved in words such as door, flower, and harmony, whereas it is lost in RP; (2) t between vowels is voiced, so that metal and matter sound very much like British medal and madder, although the pronunciation of this t is softer and less aspirated, or breathy, than the d of British English.
When a potential difference of 146 V is applied to the plates of an air-filled parallel-plate...
An air-filled capacitor consists of two parallel plates, each with an area of 7.6 cm2, separated by a distance of (a ) If a 15.0 V potential difference is applied to these plates, calculate the electric field between the plates. (b) What is the surface charge density? (c) What is the capacitance? (d) Find the charge on each plate. kV/m nC/m2
A parallel-plate air-filled capacitor having area 57 cm2 and plate spacing 1.4 mm is charged to a potential difference of 820 V. Find (a) the capacitance, (b) the magnitude of the charge on each plate, (c) the stored energy, (d) the electric field between the plates, (e) the energy density between the plates.
A parallel-plate air-filled capacitor having area 42.0 cm2 and plate spacing 1.10 mm is charged to a potential difference of 570 V. Find (a) the capacitance, (b) the magnitude of the charge on each plate, (c) the stored energy, (d) the electric field between the plates, (e) the energy density between the plates.
An air-filled capacitor consists of two parallel plates, each with an area of 7.60 cm2, separated by a distance of 1.70 mm. A 25.0-V potential difference is applied to these plates. (a) Calculate the electric field between the plates. kV/m (b) Calculate the surface charge density. nC/m2 (c) Calculate the capacitance. pF (d) Calculate the charge on each plate. pC
An air-filled capacitor consists of two parallel plates, each with an area of 7.60 cm2, separated by a distance of 2.10 mm. A 25.0-V potential difference is applied to these plates (a) Calculate the electric field between the plates kV/m (b) Calculate the surface charge density. nc/m2 (c) Calculate the capacitance. pF (d) Calculate the charge on each plate pc
A parallel-plate air-filled capacitor having area 31 cm2 and plate spacing 3.0 mm is charged to a potential difference of 400 V. Find the following values. (a) the capacitance pF (b) the magnitude of the charge on each plate nC (c) the stored energy μJ (d) the electric field between the plates V/m (e) the energy density between the plates J/m3
A parallel-plate air-filled capacitor having area 44 cm2 and plate spacing 5.0 mm is charged to a potential difference of 850 V. Find the following values. (a) the capacitance (pF) (b) the magnitude of the charge on each plate (nC) (c) the stored energy (μJ) (d) the electric field between the plates (V/m) (e) the energy density between the plates (J/m3)
The plates of an air-filled parallel-plate capacitor with a plate area of 16.5 cm2 and a separation of 8.80 mm are charged to a 130-V potential difference. After the plates are disconnected from the source, a porcelain dielectric with κ = 6.5 is inserted between the plates of the capacitor. (a) What is the charge on the capacitor before and after the dielectric is inserted? Qi = ___C Qf = ____C (b) What is the capacitance of the capacitor after...
The parallel plates in a capacitor, with a plate area of 9.90 cm2 and an air-filled separation of 2.30 mm, are charged by a 4.10 V battery. They are then disconnected from the battery and pulled apart (without discharge) to a separation of 6.50 mm. Neglecting fringing, find (a) the potential difference between the plates, (b) the initial stored energy, (c) the final stored energy, and (d) the work required to separate the plates.
A parallel-plate air-filled capacitor having area 40 cm2 and plate spacing 1.5 mm is charged to a potential difference of 830 V. Find (a) the capacitance, (b) the 2 9 5 8 0 magnitude of the charge on each plate, (c) the stored energy, (d) the electric field between the plates, (e) the energy density between the plates (a) Number (b) Number (c) Number (d) Number (e) Number Units Units Units Units Units