2.A sample of SO2 gas has a volume of 5.09×103 mL at 2.31 atm and -176.73 °C. Calculate the new temperature (in K), when the volume of the gas is decreased by 479 mL. Assume the pressure does not change.
Ans :
At constant pressure , volume of a gas is directly proportional to its temperature
It is given as :
V1T2 = V2T1C
V1 = 5.09 x 103 mL
T1 = -176.73 C = 96.42 K
V2 = 5.09 x 103 mL - 479 mL = 4.611 x 103 mL
putting values :
5.09 x 103 x T2 = 4.611 x 103 x 96.42
T2 = 87.35 K
So the new temperature will be 87.35 K
2.A sample of SO2 gas has a volume of 5.09×103 mL at 2.31 atm and -176.73...
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