What is the equilibrium Zn2+ concentration when 1.78 L of a 0.160 M zinc fluoride solution are mixed with 1.94 L of a 0.183 M ammonium phosphate solution? [Zn2+] = _______M
1) Ksp of Zn3(PO4)2 = 9*10^-33
Zn3(PO4)2(s) ----> 3Zn+2(aq) + 2PO4-3(aq)
Ksp of Zn3(PO4)2 = (3s)^3*(2s)^2
9*10^-33 = (3s)^3*(2s)^2
S = solubility of Zn3(PO4)2 = 1.53*10^-7 mole/l
Concentration of Zn+3 ion = 3s
= 3*1.53*10^-7
= 4.59*10^-7 M
What is the equilibrium Zn2+ concentration when 1.78 L of a 0.160 M zinc fluoride solution...
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