3. Why must a 3° amine (and not a 1° or 2° amine) be used in a Baylis-Hillman reaction? (Hint: notice that the amine must come off as a leaving group towards the end of the reaction.
2. A reaction discussed in class involved treating a primary amine with chloroform under basic! conditions to form an isocyanide. When a secondary amine was used instead, an amide was formed: NaOH NaOH CHCIE R-NEC + CHCIE RNH2 + Lº amine RỌNH 2° amine HANR2 2. A reaction discussed in class involved treating a primary amine with chloroform under basic conditions to form an isocyanide. When a secondary amine was used instead, an amide was formed: NaOH NaOH CHCIE R-NEC...
Please show all work. Thank you! 10. An amine is typically a poor leaving group. An amine can be converted to a good leaving group when treated with excess methyl iodide. The iodide salt is converted to the hydroxide salt using silver oxide and upon heating an E2 reaction occurs. This synthetic sequence is usually referred to as the Hofmann elimination. The reaction commonly favors the formation of the least substituted alkene. excess CH 31 R-N(CH), 1 Ag,0 - —...
Draw 3-fluoro-2-methylpropan-1-amine. 08 Question (1 point) Draw 3-fluoro-2-methylpropan-1-amine.
6) Using frontier orbital theory, explain why an E2 reaction must have the B-hydrogen and the leaving group anti-periplanar to each other.
6) Using frontier orbital theory, explain why an E2 reaction must have the B-hydrogen and the leaving group anti-periplanar to each other.
please help me with this short answer portion i am confused 1. Explain why a catalyst must affect the rate of a reaction in both directions. 2. Calculate the concentration of a noncompetitive inhibitor (K yield 90% inhibition of an enzyme-catalyzed reaction. 2 x 10 M) need 3. For the operator (sin0/cos8)(d/de) and the eigenfunction sine, the eigenvalue a) sine b) 1 c) -sine d) -1 e) -cose 4. Evaluate numerically . Hint: use Euler formula. Show your work clearly...
1. Preparation of 2-chloro-2-methylbutane from 2-methyl-2-butanol involves Sw1 reaction mechanism. What does Sw1 mean? (1 pts) 2. This reaction prefers to undergo via Sw1 mechanism over Sw2. Why? (3 pts) 3. Write the structure of carbocation and nucleophile involved in this reaction. (2 pts) 4. Substrate alcohol (2-methyl-2-butanol) consists a poor leaving group (OH group). How do you covert this poor leaving group into good leaving group? (2 pts) 5. Which will be the bottom layer between aqueous and organic...
1.What could be an alternate name for 2-aminobutane? Question 1 options: terbutyl amine isobutyl amine 2-butanamine 1-butanamine 2.Which pairing of general formula and compound class is incorrect? Question 2 options: R3CNH2; tertiary amine. RC=O NH2; amide. R2NH; secondary amine. RNH2; primary amine 3.Which of the following is not a primary amine? Question 3 options: 3-Hexylamine. Cyclohexylamine. Diethylamine. 1-Butylamine 4. When many copy molecules of the amine below are explored, which of the following amines do you expect NO to make...
PS questions 1. (2 pt) Which is the correct structure for (R)-N-ethyl-3-methylcyclopent-2-en-1-amine? A INHEt Et > NHEN VEt | ANH NHA | NHẤt A 2. (2 pt) Which is the correct name for the structure? HN1 A. (4R,7R)-4-(3-methoxyphenyl)-N-methyloctan-7-amine B. (48,7R)-4-(3-methoxyphenyl)-N-methyloctan-7-amine C. (2R,5S)-5-(3-methoxyphenyl)-N-methyloctan-2-amine D. (2R,5R)-5-(3-methoxyphenyl)-N-methyloctan-2-amine OMe 3. (3pt) Why is HONH2 more basic? Note the pka values are for the conjugate acids. HONH2 ZI A. diphenylamine has more resonance structure after protonation B. the Nitrogen electrons on diphenylamine can resonanate into...
2. (18 pts) Draw a valid structure that contains one 1° alcohol, one 2° amine, one 3° halide, an allyl functional group, an ether functional group, and only one chiral carbon. (b) Name the structure you drew in part (a). (c) Draw a valid resonance structure for your structure in (a) and a mechanism to show how it forms.