In a certain county 35% of the people have more than one sibling. Suppose a simple...
In a certain county 35% of the people have more than one sibling. Suppose a simple random sample of 650 people is selected. Use the central limit theorem to calculate the probability that less than 37% of these people have more than one sibling.
Homework Answers
| for normal distribution z score =(p̂-p)/σp | |
| here population proportion= p= | 0.350 |
| sample size =n= | 650 |
| std error of proportion=σp=√(p*(1-p)/n)= | 0.0187 |
| probability = | P(X<0.37) | = | P(Z<1.07)= | 0.8577 |
(try 0.8575 if this comes wrong and revert)
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