Convert -11310 to an 8-bit two’s complement binary integer.
Please explain the steps.
The task asked in the question is a very basic task to convert a given decimal into its 2's complementary binary representation.
Well to convert any binary representation to 2's complement, we have to first reverse all the 1's to 0's and 0's to 1's. After doing this we have to add 1 to the new reversed binary number. The resultant will be our result.
So binary representation of 11310 ---> 10110000101110
So to convert a decimal into a binary we just recursively divide the decimal with 2 and note the remainder (either 1 or 0) and finally write the whole remainder series in reverse.
for eg
Decimal number = 7
7/2 remainder = 1
3/2 remainder= 1
and then the final quotient is also 1
So writing the series in reverse order we get = 111
So after getting the binary representation of 11310 which is 10110000101110 we reverse the digits (0-->1 and 1-->0)
S0 new representation = 01001111010001
and then finally add 1 to it So the 2's complement is 01001111010010
So the 2's complement of -11310 is = 01001111010010
Convert -11310 to an 8-bit two’s complement binary integer. Please explain the steps.
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