Question

Create a java program.Input 10 integers in the main function using for loop. Determine the largest and smallest number. Create and call the following methods.
max() --> to determine the largest number
--> must have two (2) parameters only
   --> must return integer
min() --> to determine the smallestnumber
--> must have two (2) parameters only
   --> must return integer
display the result in the main function

Answer 1

Copy to your IDE for a better view!

CODE:

import java.io.*;
import java.util.Scanner;
class MaxMin {
   public static void main (String[] args) {
       int a[]; //declaring array a
       a=new int[10]; //allocating memory of 10 elements
       Scanner in = new Scanner(System.in);
       for(int i=0;i<10;i++)
       {
       a[i] = in.nextInt();//taking input from user
       }
       int M=max(a,10);//calling max function
       System.out.println("Max number is "+ M);
       int m=min(a,10);//calling minimum function
       System.out.println("Min number is "+ m);
   }
   public static int max(int a[],int n)
   {
   int M=a[0];// asuming first number as maximum
   for(int i=1;i<n;i++)
   {
   if(a[i]>M)//if ith number is more than assumed
   {
   M=a[i];//change M to ith number
   }
   }
   return M;
   }
   public static int min(int a[],int n)
   {
   int m=a[0];// asuming first number as minimum
   for(int i=1;i<n;i++)
   {
   if(a[i]<m)//if ith number is less than assumed
   {
   m=a[i];//change M to ith number
   }
   }
   return m;
   }
}

code screenshot:

Input :

output:

If any queries do comment!

Upvote, Please!

All the best!