From 89 of its restaurants, Noodles & Company managers
collected data on per-person sales and the percent of sales due to
"potstickers" (a popular food item). Both numerical variables
failed tests for normality, so they tried a chi-square test. Each
variable was converted into ordinal categories (low, medium, high)
using cutoff points that produced roughly equal group sizes. At
α= .10, is per-person spending independent of percent of
sales from potstickers?
Potsticker % of Sales | ||||||||||||
Per-Person Spending | Low | Medium | High | Row Total | ||||||||
Low | 13 | 12 | 5 | 30 | ||||||||
Medium | 9 | 12 | 2 | 23 | ||||||||
High | 6 | 15 | 15 | 36 | ||||||||
Col Total | 28 | 39 | 22 | 89 | ||||||||
(a) The hypothesis for the given issue is
H0: Percentage of Sales and
Per-Person Spending are independent.
No | |
Yes |
(b)
Calculate the chi-square test statistic, degrees of freedom, and
the p-value. (Round your test statistic value to 2
decimal places and p-value to 4 decimal places. Leave no
cells blank - be certain to enter "0" wherever
required.)
Test statistic | |
d.f. | |
p-value | |
(c) We reject the null and find
dependence.
Yes | |
No |
(a) Yes.
H0: Percentage of Sales and Per-Person Spending are independent.
(b) Test statistics = 12.14
df = (3-1) * (3-1) = 4
p-value = 0.0163
(c) yes, we reject null hypothesis and found dependence. since p-value < 0.10
From 89 of its restaurants, Noodles & Company managers collected data on per-person sales and the...
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