I'm trying to learn acids and bases and I can't figure out CoCl2's solubility in water...
Homework Answers
CoCl2 is fairly soluble in water. In pure water it forms the following equilibrium at sarurated condition.
CoCl2(s)
Co2+
(aq) + 2Cl- (aq)
Now , when HCl is added , it dissociates to form H+ and Cl- ion the solution . So on addition of HCl to aqueous solution of CoCl2 the concentration of product (Cl-) increases. By Le-chateliers principle with increasing concentration of product the system shifts towards left side (reactant side) thus dissociation of CoCl2 is suppressed . Hence solubility of CoCl2 decreases in presence of common ion Cl-. Such effect is called common ion effect.
So, CoCl2 is more soluble in water than in HCl solution.
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I'm
trying to learn acids and bases and I can't figure out CoCl2's
solubility in water...
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figure it out for a while, but I can't figure it out.
Also, I do know that the answer is provided here. While I know
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However, I'm totally lost on how they...
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can you please help me figure out my unknown no, it is part of what i am trying to figure out. Based off of solubility and functional group testing it is a weak acid/ phenol and aromatic
can
you please help me figure out my unknown
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what
is solution ?
(References) Strong acids and strong bases ionize 100% in aqueous solution - HCl is a strong acid. In solution we write it as H(aq) + Cl(aq). - HF is a weak acid. In solution we write it as HF (aq). - KOH is a strong base. In solution we write it as K (aq) + OH(aq). - NH3 is a weak base. In solution we write it as NH3(aq). Exception: Since Ca(OH)2 is only slightly soluble...
Please help me figure out how to take the derivative of "Y" in
respect to "PY" of this equation. I've been trying to
figure it out for a while, but I can't figure it out.
Also, I do know that the answer is provided here. While I know
the answer I'm not quite following how they did what they did. I
think I understand how they got the first part of the answer.
However, I'm totally lost on how they...
I'm trying to figure out this answer; but I only know that it is
NOT a N.R... It is the problem with the
(2-bromo-1,2,3-trimethylcyclohexane) and potassium tert-butoxide
and its conjugate acid.
can anyone tell me if this is right??
LE2 1. KH NR. 2. BF laryl halide 1 H₃C KOLBu bhong нег Br wave' HOIBU Hoffman H3C nud. a pronic NH, CHI - electrop II rah HEDMSO CH3 / NCH 1 Il Br AgNO3 SN1 EL E tOH, Ano al...
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stuck on if u-sub is necessary.
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can
you please help me figure out my unknown
no,
it is part of what i am trying to figure out. Based off of
solubility and functional group testing it is a weak acid/ phenol
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