Question

Question: File response. You must create a program called “Assigment_Mod9.cpp” that allow to manage the inventory of a store. The program must have a menu that allow to perform the following three actions:

Add a new item

Remove an item

Replicate n times and existing item

The program must have two dynamic arrays: one for store the name of the product and other to store the price of the product. The size of each array must be of the same number as products in the store. Each action must be performed by a function that receives the corresponding parameter to execute each action.

Answer 1

Below is the implementation of the problem in C++:

#include <iostream>
using namespace std;
int size=0;//size of both arrays initially
string *name = new string[size]; //dynamic array to store product name
float *price=new float[size]; //dynamic array to store product price

//fuction to display/ replicate the data
void display()
{
cout<<"\n______Displaying Data_________\n";
cout<<"\nProduct Name\t Price\n---------------------";
for(int i=0;i<size;i++)
cout<<"\n"<<name[i]<<" \t:\t"<<price[i];
}

//fuction to add an item. n is name and p is price
//we used temporary arrays inorder to increase the size dynamically
void addItem(string n, float p)
{
size=size+1; //increase the size by 1
string *nm = new string[size]; //temporary array to store names
float *cost=new float[size]; //temporary array to store prices
int i=0;
//copy data into temporary arrays
for( i=0;i<size-1;i++)
{
nm[i]=name[i];
cost[i]=price[i];
}
nm[i]=n; //assign new name and price at the end of the array
cost[i]=p;
delete [] name; //delete original array as there are of size : size-1
delete [] price;
name = new string[size];
price = new float[size];

//store again the newly created array into old one
for( i=0;i<size;i++)
{
name[i]=nm[i];
price[i]=cost[i];
}

delete [] nm; //delete temporary arrays
delete [] cost;
}

//fuction that removes specific element from array by it's name
void removeItem(string nm)
{
int index=-9; //index of element to be deleted
for(int i=0;i<size;i++)
if(name[i]==nm) //element found
index=i; //mark index

if(index==-9) //not found
cout<<"\nData not found!!";
else //found
{
//if element is not at the last positon then
//shift all the element at i+1 locaion to ith locaion
if(index!=(size-1))
{ for(int i=index;i<size-1;i++)//
{
name[i]=name[i+1];
price[i]=price[i+1];
}
}
//last location is to be deleted
size=size-1;//reduce the size
string *nm1 = new string[size];//temporary arrays
float *cost1=new float[size];
int i=0;
//copy elements into temporary arrays
for( i=0;i<size;i++)
{
nm1[i]=name[i];
cost1[i]=price[i];
}
  
delete [] name;// delete old sized arrays
delete [] price;
  
name = new string[size];//create new size arrays
price = new float[size];
//copy elements into original arrays
for( int i=0;i<size;i++)
{
name[i]=nm1[i];
price[i]=cost1[i];
}
delete [] nm1; //delete temporary arrays
delete [] cost1;

}

}
int main()
{
int ch=1;
string nm;
float p;
while(ch>0&&ch<4)
{
//menu display
cout<<"\n______MENU________\n1. Add item\n2.Remove Item\n3.Display items\n4.Close Application";
cout<<"\n enter your choice: ";
cin>>ch;
int nsize;
switch(ch)
{
case 1: //case to add item
cout<<"enter item name: ";
cin>>nm;
cout<<"Enter price: ";
cin>>p;
addItem(nm,p);
break;
case 2://remove the item
cout<<"enter the item name you want to remove: ";
cin>>nm;
removeItem(nm);
break;
case 3:display(); //display choice
break;
case 4: //exit Application
break;
default:cout<<"\n You entered wrong choice!!";
break;
}
}
return 0;
}

Below is the screenshot of the code:

Screenshot of output:

Note: code is taking input from standard I/O. Press 'enter' key after each input.