what is the empirical formula for Al2(SO4)3
What is the empirical formula for C6H10
1) Al2(SO4)3
empirical formula is simplest form of compound Al2(SO4)3 is already simplest formula
empirical formula = molecular formula = Al2(SO4)3
2) C6H10 simplest formula = C6H10
so empirical formula = molecular formula = C6H10
what is the empirical formula for Al2(SO4)3 What is the empirical formula for C6H10
a) How many mol of Al2(SO4)3 are required to make 40 mL of a 0.050 M Al2(SO4)3 solution? (Hint, molarity is moles per liter. You know the molarity. You are given the number of mL's, which can be converted to liters. Just set it up so the units cancel and you get "moles".) moles Al2(SO4)3 b) What is the molecular weight of Al2(SO4)3, to the nearest gram? c) What mass of Al2(SO4)3 is required to make 40 mL of a 0.050 M...
a) How many moles of Al2(SO4)3 are required to make 44 mL of a 0.090 M Al2(SO4)3 solution? (Hint, molarity is moles per liter. You know the molarity. You are given the number of mL's, which can be converted to liters. Just set it up so the units cancel and you get "moles".) moles Al2(SO4)3 b) What is the molecular weight of Al2(SO4)3, to the nearest gram? grams c) What mass of Al2(SO4)3 is required to make 44 mL of...
2Al(OH)3 + 3H2SO4 -----> Al2(SO4)3 + 6H2O In the above reaction, how many moles of Al2(SO4)3 would be produced by the reaction of 3.8 moles of H2SO4 ?
what is the concentration of the sulfate ion in 1.1M AL2(SO4)3 solution
a) How many moles of Al2(SO4)3 are required to make 55 mL of a 0.050 M Al2(SO4)3 solution? (Hint, molarity is moles per liter. You know the molarity. You are given the number of mL's, which can be converted to liters. Just set it up so the units cancel and you get "moles".) moles Al2(SO4)3 b) What is the molecular weight of Al2(SO4)3, to the nearest gram? grams c) What mass of Al2(SO4)3 is required to make 55 mL of...
Determine the mass of oxygen in a 7.2-g sample of Al2(SO4)3. Tie the liquid fuel in lighters How many aran 22) A compound contains the elements C, H, N, and O. When a 1.2359 g sample is burned for elemental analysis, 2.241 g of CO2 gas are formed. The combustion also showed that the sample contained 0.0648 g of H and 0.3564 g of N. Determine the empirical formula of the compound.
a) How many moles of Al2(SO4)3 are required to make 43 mL of a 0.060 M Al2(So4)3 solution? (Hint, molarity is moles per liter. You know the molarity. You are given the number of mL's, which can be converted to liters. Just set it up so the units cancel and you get "moles".) moles Al2(SO4)3 b) What is the molecular weight of Al2(S04)3, to the nearest gram? grams c) What mass of Al2(SO4)3 is required to make 43 mL of...
(Express your answer as a chemical formula.) a 3CuSO4 + 2A1 - Al2(SO4)3 + 3Cu is the oxidizing agent. is the reducing agent. b. Cu+S Cus is the oxidizing agent. is the reducing agent. c. 4Fe + 10HNO3 -- 4Fe(NO3)2 + NH4NO3+ 3H20 is the oxidizing agent. is the reducing agent. d. 2FeCl3 - Cl- 2FeCl3 is the oxidizing agent. is the reducing agent.
Consider the reaction: 2 Al(OH)3 + 3 H2SO4 à Al2(SO4)3 + 6H2O. How many grams of Al2(SO4)3 are generated when 152 g of H2SO4 reacts? Show Work on Scratch Paper! O 530.g of Al2(SO4)3 O 1590 g of Al2(SO4)3 177 g of Al2(SO4)3 43.6 g of Al2(SO4)3 131 g of Al2(SO4)3
what kind of reaction is this: 3CuSO4 + 2 Al --> 3Cu + Al2(SO4)3 is it a double replacement or a redox reacton?