When 0.129 moles of HCl reacts with 0.235 moles of NH3, how much NH3 is consumed?

Question

Question

When 0.129 moles of HCl reacts with 0.235 moles of NH₃, how much NH₃ is consumed?

Answer 1

Answer #1

Balanced chemical equation is:

HCl + NH3 ---> NH4Cl

1 mol of HCl reacts with 1 mol of NH3

for 0.129 mol of HCl, 0.129 mol of NH3 is required

But we have 0.235 mol of NH3

so, HCl is limiting reagent

According to balanced equation

mol of NH3 reacted = (1/1)* moles of HCl

= (1/1)*0.129

= 0.129 mol

Answer: 0.129 mol

Answer 2

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