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PART A The activation energy of a certain reaction is 30.7 kJ/mol . At 20 ∘C,...

PART A

The activation energy of a certain reaction is 30.7 kJ/mol . At 20 ∘C, the rate constant is 0.0130 s−1. At what temperature would this reaction go twice as fast? Express your answer numerically in degrees Celsius

Part B

Given that the initial rate constant is 0.0130 s−1 at an initial temperature of 20 ∘C, what would the rate constant be at a temperature of 100 ∘C? Express your answer numerically in inverse seconds.

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