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Part A) The activation energy of a certain reaction is 33.9 kJ/mol . At 20 ∘...

Part A) The activation energy of a certain reaction is 33.9 kJ/mol . At 20 ∘ C , the rate constant is 0.0160 s −1 . At what temperature in degrees Celsius would this reaction go twice as fast? Express your answer with the appropriate units. Answer was: T 2 = 35 ∘ C

Part B Given that the initial rate constant is 0.0160 s −1 at an initial temperature of 20 ∘ C , what would the rate constant be at a temperature of 140. ∘ C for the same reaction described in Part A?

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