The initial kinetic energy of a block moving on a horizontal floor is 48 J. A constant frictional force acts on the block bringing it to rest over a distance of 2 m. What is the frictional force on the block?
work done = change in kinetic energy
W = Final kinetic energy - initial kinetic energy
= 0 - 48 = -48J
work done by frictional force = F*d*cos a
-48 = F*2*cos 180
F= 24 N
so the frictional force on the block is 24 N
The initial kinetic energy of a block moving on a horizontal floor is 48 J. A...
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