Question

10.11 LAB: Fat-burning heart rate

Write a program that calculates an adult's fat-burning heart rate, which is 70% of 220 minus the person's age. Complete fat_burning_heart_rate() to calculate the fat burning heart rate.

The adult's age must be between the ages of 18 and 75 inclusive. If the age entered is not in this range, raise a ValueError exception in get_age() with the message "Invalid age." Handle the exception in __main__ and print the ValueError message along with "Could not calculate heart rate info."

Ex: if the input is:

35

The output is:

Fat burning heart rate for a 35 year-old: 129.5 bpm

If the input is:

17

The output is:

Invalid age.

Could not calculate heart rate info.

Heres some of the code I have already. Please keep it similiar to this

def get_age():
try:
age = int(input())
if age < 18 or age > 75:
raise ValueError('Invalid age.')
return age

def fat_burning_heart_rate(age):
heart_rate = 154 - age
return heart_rate

if __name__ == "__main__":
except ValueError as excpt:
print(excpt)
print('Could not calculate heart rate info.')
age = get_age()

Answer 1

Solution:

Program:

def get_age(): #function to read age from inputs
age=int(input())
if age<18 or age >75: #check age validity
raise ValueError("Invalid age.") #If age is not valid, raise exception
return age #If age is valid, return age
  

def fat_burning_heart_rate(age): #function to calculate heart rate
  
heart_rate=220-age #calculate 70% of 220 minus age
heart_rate*=0.7
return heart_rate #return heart rate

if __name__=="__main__":
try: #try block of statements
age=get_age()
rate=fat_burning_heart_rate(age) #call method to calculate heart rate
print("Fat burning rate for a ",age," year-old:",end="") #print result
print(rate,"bpm")
except ValueError as excpt: #If exception occurs, handle them with printing message on console
print(excpt)
print("Could not calculate heart rate info.")
  

Screenshots:

The screenshots of the program execution are attached below for reference. Please follow them for indentation.