Give all answers to 4 decimal places.
For a standard normal distribution:
a) find the probability a score is between the mean and 0.85 standard deviations above the mean?
b) find the probability a score is between the mean and 0.85 standard deviations below the mean?
c) If the probability that a person scores below a particular value is 0.17, then the probability a person scores above that value equals?
d) If the probability that a person scores between a particular positive z value and the mean is 0.2, then the probability a person scores above that value equals?
a) find the probability a score is between the mean and 0.85 standard deviations above the mean?
Solution:
We have to find P(0<Z<0.85)
P(0<Z<0.85) = P(Z<0.85) – P(Z<0) = 0.802337 – 0.5 = 0.302337
Required probability = 0.3023
b) find the probability a score is between the mean and 0.85 standard deviations below the mean?
We have to find P(-0.85<Z<0)
P(-0.85<Z<0) = P(Z<0) – P(Z<-0.85) = 0.5 - 0.197663 = 0.302337
Required probability = 0.3023
c) If the probability that a person scores below a particular value is 0.17, then the probability a person scores above that value equals?
We are given P(Z<z) = 0.17
We have to find P(Z>z)
P(Z>z) = 1 – P(Z<z) = 1 – 0.17 = 0.83
Required probability = 0.8300
d) If the probability that a person scores between a particular positive z value and the mean is 0.2, then the probability a person scores above that value equals?
We are given P(0<Z<z) = 0.2
We have to find P(Z>z) = 0.5 – 0.2 = 0.3
Required probability = 0.3000
Give all answers to 4 decimal places. For a standard normal distribution: a) find the probability...
To FOUR DECIMAL PLACES: Determine the area under the standard normal curve that lies to the left of Z = –1.31 to the right of Z = –2.47 between Z = –2.47 and Z = –1.31 between Z = 1.31 and Z = 2.47 Find the z-scores that separate the middle 84% of the standard normal distribution from the area in the tails. Find z0.18 a. Find the Z-score corresponding to the 72nd percentile. In other words, find the Z-score...
For a normal distribution, verify that the probability (rounded to two decimal places) within a) 2.23 standard deviations of the mean equals ________ b) Find the probability that falls within 1.35 standard deviations of the mean.
1) Given a standard normal distribution, find the probability of having a z score higher than 1.67 ```{r} ``` 2) Given that test scores for a class are normally distributed with a mean of 80 and variance 36, find the probability that a test score is lower than a 45. ```{r} ``` 3) Given a standard normal distribution, find the Z score associated with a probability of .888 ```{r} ``` 4) Find the Z score associated with the 33rd quantile...
For a standard normal distribution, find: P(z > -2.52) (round to 3 decimal places) For a standard normal distribution, find: P(-2.56 < z < -2.52) (round to 3 decimal places) For a standard normal distribution, find: P(z > c) = 0.2726 Find c. (round to 2 decimal places) A manufacturer knows that their items have a normally distributed lifespan, with a mean of 5.3 years, and standard deviation of 1.7 years. If you randomly purchase one item, what is the probability it...
7. For a standard normal distribution, find: P(z < c) = 0.1164 Find c rounded to two decimal places. 8.For a standard normal distribution, find: P(z > c) = 0.89 Find c rounded to two decimal places 9.About ___% of the area under the curve of the standard normal distribution is between z=-0.426 and z=0.426 (or within 0.426 standard deviations of the mean). 10.About ___% of the area under the curve of the standard normal distribution is outside the interval...
A distribution of values is normal with a mean of 238 and a standard deviation of 93.7. Find the probability that a randomly selected value is between 219.3 and 481.6. P(219.3<x< 481.6) = Enter your answer as a number accurate to 4 decimal places. Answers obtained using exact z-scores or z-scores rounded to 3 decimal places are accepted.
In a standard normal distribution, find the following values: The probability that a given z score is less than -2.67 The probability that a given z score is between 1.55 and 2.44 The z scores that separates the most inner (middle) 82% of the distribution to the rest The z score that separate the lower 65 % to the rest of the distribution
1) Find the area under the standard normal curve to the right of z= -0.62. Round your answer to four decimal places. 2) Find the following probability for the standard normal distribution. Round your answer to four decimal places. P( z < - 1.85) = 3) Obtain the following probability for the standard normal distribution. P(z<-5.43)= 4) Use a table, calculator, or computer to find the specified area under a standard normal curve. Round your answers to 4 decimal places....
For a standard normal distribution, find: P(z < -0.85) Express the probability as a decimal rounded to 4 decimal places. . Incorrect Get help: VideoVideo Box 1: Enter your answer as an integer or decimal number. Examples: 3, -4, 5.5172 Enter DNE for Does Not Exist, oo for Infinity
3. A normal distribution of BMCC MATSI scores has a standard deviation of 1.5. Find the z-scores corresponding to each of the following values: a. A score that is 3 points above the mean. b. A score that is 1.5 points below the mean. c. A score that is 2.25 points above the mean 4. Scores on BMCC fall 2017 MATI50.5 department final exam form a normal distribution with a mean of 70 and a standard deviation of 8. What...