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Suppose for a certain microRNA of size 20, the probability of getting a purine is binomially...

Suppose for a certain microRNA of size 20, the probability of getting a purine is binomially distributed with a probability of 0.7. There are 100 of these microRNAs, each independent of the other. Let Y denote the average number of purine in these microRNAs. Find the probability that Y is greater than 15.

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Answer #1

Y follows Binomial (100, 0.7)

P(Y=y) = 100​​​​Cy * 0.7y * 0.3100-y

P(Y>15) = Sum all values of y from 16 to 100 over P [Y=y)

P(Y>15) =   0.999999

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