Dinitrogen tetroxide decomposes to nitrogen dioxide. Write the balanced chemical equation for this reaction. Start with pure N2O4 at 1.00 atm. Find the equilibrium partial pressures of N2O4 and NO2. The equilibrium constant for this reaction is K = 11.
N2O4 (g) 2 NO2 (g)
Initial pressure 1.00 0
Change in pressure - X 2X
Equilibrium pressure (1.00 - X) 2X
or, 11 = (2X)2/(1.00 - X)
or, 11 = 4X2/(1.00 - X)
or, 4X2 + 11X - 11 = 0
or,
or,
or,
or, X = 0.775 atm, - 3.53 atm
The acceptable value of X = 0.775 atm as partial pressure can not be negative.
Therefore, the equilibrium partial pressure of N2O4 = (1.00 - 0.775) = 0.225 atm
And the equilibrium partial pressure of NO2 = 2 x 0.775 = 1.55 atm
Dinitrogen tetroxide decomposes to nitrogen dioxide. Write the balanced chemical equation for this reaction. Start with...
Dinitrogen tetroxide decomposes to nitrogen dioxide: N2O4(g)→2NO2(g)ΔHorxn= 55.3kJ At 298 K, a reaction vessel initially contains 0.100 atm of N2O4. When equilibrium is reached, 58% of the N2O4 has decomposed to NO2. What percentage of N2O4 decomposes at 380 K ? Assume that the initial pressure of N2O4 is the same (0.100 atm).
Dinitrogen tetroxide decomposes to nitrogen dioxide: N2O4(g)→2NO2(g) ΔrH∘=55.3kJmol−1 At 298 K, a reaction vessel initially contains 0.100 bar of N2O4. When equilibrium is reached, 58% of the N2O4 has decomposed to NO2. What percentage of N2O4 decomposes at 389 K? Assume that the initial pressure of N2O4 is the same (0.100 bar). Please use bar and not atm.
Dinitrogen tetroxide decomposes to nitrogen dioxide: N2O4(g)→2NO2(g) ΔrH∘=55.3kJmol−1 At 298 K, a reaction vessel initially contains 0.100 bar of N2O4. When equilibrium is reached, 58% of the N2O4 has decomposed to NO2. What percentage of N2O4 decomposes at 369 K? Assume that the initial pressure of N2O4 is the same (0.100 bar)
4 The value of Kp for the reaction of dinitrogen tetroxide to make nitrogen dioxide is 12.1786. The partial pressure of dinitrogen tetroxide 1.3114 atm with no nitrogen dioxide. What is the equilibrium partial pressure (in atm) of nitrogen dioxide?
Dinitrogen tetroxide decomposes to form nitrogen dioxide in a second-order reaction: N2O4(g) → 2NO2(g) At 400.0 K, the rate constant for this reaction has been measured to be 2.9 × 108 L/(mol • s). Suppose 0.222 mol of N2O4(g) is placed in a sealed 41.7-L container at 400.0 K and allowed to react. What is the total pressure inside the vessel after 32.9 ns has elapsed? (R = 0.0821 (L • atm)/(K • mol)) a. 0.183 atm b. 0.175 atm...
Dinitrogen tetroxide decomposes to produce nitrogen dioxide: N204 (9) - 2 NO2 (g) Calculate the equilibrium constant for the reaction given the equilibrium concentrations at 100°C: [N204] = 0.800 M and [NO2] = 0.400 M A. 5.00 OB.0.200 OC. 0.500 OD.2.00
At high temperatures, dinitrogen tetroxide gas decomposes to nitrogen dioxide gas. At 500 oC, a sealed vessel containing some dinitrogen tetroxide gas was allowed to reach equilibrium. At equilibrium, the mixture contained 3.92 M dinitrogen tetroxide gas. Calculate the equilibrium concentration of nitrogen dioxide if KC at this temperature is 0.559.
2. For the equilibrium between dinitrogen tetroxide and nitrogen dioxide: N204 = 2 NO2 Suppose that both the forward and reverse reactions are elementary processes with rate constants of k, and kr respectively, and the equilibrium constant for the process is 14.48 at 298 K. If the rate of the reverse reaction is 1324 M/s when (NO2) = 0.60 M, what is the half-life for the decomposition of dinitrogen tetroxide (the forward reaction) at the same temperature?
The value of Kc for the reaction of dinitrogen tetroxide to make nitrogen dioxide is 2.3776. The concentration of nitrogen dioxide 1.4331 M with no dinitrogen tetroxide. What is the equilibrium concentration (in M) of nitrogen dioxide?
When heated, colorless dinitrogen tetraoxide, N2O4(g), decomposes into red-brown nitrogen dioxide, NO2(g), according to the following reaction: N204 (g) + 2 NO2 (g) Suppose that 2.00 mol of N204(g) was placed into an empty 5.00-L flask and heated to 407 K. When equilibrium was attained, the concentration of red-brown NO2(g) was found to be 0.525 M. Calculate the equilibrium constant, K, for this reaction at 407 K. 3.80 2.00 0.500 0.263 0.525