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Dinitrogen tetroxide decomposes to nitrogen dioxide: N2O4(g)→2NO2(g) ΔrH∘=55.3kJmol−1 At 298 K, a reaction vessel initially contains...

Dinitrogen tetroxide decomposes to nitrogen dioxide: N2O4(g)→2NO2(g) ΔrH∘=55.3kJmol−1 At 298 K, a reaction vessel initially contains 0.100 bar of N2O4. When equilibrium is reached, 58% of the N2O4 has decomposed to NO2.

What percentage of N2O4 decomposes at 369 K? Assume that the initial pressure of N2O4 is the same (0.100 bar)

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Answer #1

N₂O4 = 2002 0.1 E 0.1-x an 22 sez amount de composed x = 0.1 * 58 100 = 0.058 bar (21)2 12 0.058 ) : K298 = PRO PN2ou 0.1-R

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