Question

Calculate [Fe3+] and [SCN-] for each of the nine trials. Show the calculations for Sample 1

calibration curve is y=3967.7x-0.0822

the R^2 value is y=0.09959

Solution [SCN-1 2.06764 Stock solution B Absorbance Dilution 1 (50.0%) 1.0 xl-4 0.723 Dilution 2 (25.0%) S.Oxon Dilution 3 (1Chemical Equilibrium Calculation of the Equilibrium Constant Calculate (FeSCNL for each of the nine trials. Show the calculat

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Answer #1

We can determine the concentration of Fe(SCN)2+ from the absorbance values and the calibration curve (remember that the x variable represents concentration and the y variable represents absorbance). For Trial 1:

C A+ 0.0822 3967.7M- 1 0.136 + 0.08225 3967.7M-1 50 r10-5M 390

The initial concentration of SCN- si given by the dilution formula:

Cstock. Vstock C = 0.00200M. Iml 12 = 2.00c10-4M 10mL Vfinal

And the concentration in equilbrium is the difference between this value and the concentration consumed to produce Fe(SCN)2+, which we just calculated:

2.00x10-4 M - 5.50x10-5 M = 1.45x10x10-4 M

The same for Fe3*, its initial concentration is.

C =- Cstock. Vstock Vfinal 0.00200M 9mL ML = 1.8x10-3M 10mL

And its equilibrium concentration is:

1.8x10-3 M - 5.50x10-5 M = 1.75x10-3 M.

For all of the samples, the results are (commas are decimal separators):

Sample V Fe(III) V SCN- Absorbance [FeSCN(II)] eq [Fe(III)] eq [SCN-] eq
1 9 1 0,136 5,50E-05 1,75E-03 1,45E-04
2 8 2 0,23 7,87E-05 1,52E-03 3,21E-04
3 7 3 0,307 9,81E-05 1,30E-03 5,02E-04
4 6 4 0,378 1,16E-04 1,08E-03 6,84E-04
5 5 5 0,428 1,29E-04 8,71E-04 8,71E-04
6 4 6 0,416 1,26E-04 6,74E-04 1,07E-03
7 3 7 0,406 1,23E-04 4,77E-04 1,28E-03
8 2 8 0,349 1,09E-04 2,91E-04 1,49E-03
9 1 9 0,272 8,93E-05 1,11E-04 1,71E-03
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