A consumer advocate claims that 80 percent of cable television subscribers are not satisfied with their cable service. In an attempt to justify this claim, a randomly selected sample of cable subscribers will be polled on this issue. Suppose that the advocate’s claim is true, and suppose that a random sample of five cable subscribers is selected. Assuming independence, use an appropriate formula to compute the probability that four or more subscribers in the sample are not satisfied with their service.
Minitab instructions: Go to Calc > select Probability Distributions > select Binomial > select Cumulative probability > Number of Trials insert 5 > Event Probability insert “.8” > Input Constant insert “3.” Click OK.
Paste your Minitab results here and then show your work to calculate P(x ≥ 4) = 1 – P(x ≤ 3)
from minitab:
output:
Cumulative Distribution Function
Binomial with n = 5 and p = 0.8
x P( X ≤ x )
3 0.26272
therefore
P(x ≥ 4) = 1 – P(x ≤ 3) =1-0.26272 =0.73728
A consumer advocate claims that 80 percent of cable television subscribers are not satisfied with their...
A consumer advocate claims that 70 percent of cable television subscribers are not satisfied with their cable service. In an attempt to justify this claim, a randomly selected sample of cable subscribers will be polled on this issue. (a) Suppose that the advocate's claim is true, and suppose that a random sample of 4 cable subscribers is selected. Assuming independence, use an appropriate formula to compute the probability that 3 or more subscribers in the sample are not satisfied with...
A consumer advocate claims that 85 percent of cable television subscribers are not satisfied with their cable service. In an attempt to justify this claim, a randomly selected sample of cable subscribers will be polled on this issue. (a) Suppose that the advocate's claim is true, and suppose that a random sample of 8 cable subscribers is selected. Assuming independence, use an appropriate formula to compute the probability that 7 or more subscribers in the sample are not satisfied with...
A consumer advocate claims that 70 percent of cable television subscribers are not satisfied with their cable service. In an attempt to justify this claim, a randomly selected sample of cable subscribers will be polled on this issue. (a) Suppose that the advocate's claim is true, and suppose that a random sample of 5 cable subscribers is selected. Assuming independence, use an appropriate formula to compute the probability that 3 or more subscribers in the sample are not satisfied with...
epolled on this issue, A consumer advocate claims that 85 percent of cable television subscribers are not satisfied vwith their cable service. In n attempt to justify this claim, a randomly selected sample of cable subscribers will nthe sample are not satisfied formula to compute the probability that 6 or more subscribers h i end Do not round intormediat ealuations Rund Fnal anewor to in 2 decimal place Bound other final angere to d decimal pics 85 Binomial, n. Probability...
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Two different companies have applied to provide cable television service in a certain region. Let p denote the proportion of all potential subscribers who favor the first company over the second. Consider testing H0: p = .5versus Ha: p ≠ .5 based on a random sample of 25 individuals. Let X denote the number in the sample who favor the first company and x represent the observed value of X. a. Which of the following rejection regions is most appropriate...
Two different companies have applied to provide cable television service in a certain region. Let p denote the proportion of all potential subscribers who favor the first company over the second. Consider testing Ho: p=0.5 versus Ha: p?0.5 based on a random sample of 25 individuals. Let the test statistic X be the number in the sample who favor the first company and x represent the observed value of X. a) Describe type I and type II errors in the...
The Binomial and Poisson Distributions Both the Binomial and Poisson Distributions deal with discrete data where we are counting the number of occurrences of an event. However, they are very different distributions. This problem will help you be able to recognize a random variable that belongs to the Binomial Distribution, the Poisson Distribution or neither. Characteristics of a Binomial Distribution Characteristics of a Poisson Distribution The Binomial random variable is the count of the number of success in n trials: number of...