ozone can be created from oxygen gas (with an input of energy) via the following reaction:
3O2(g)=2O3(g)
If the equilibrium constant, K, is 1.12 * 10^-54 for this reaction at a particular temperature and [O2]= 3.10*10^-2 M at equilibrium, what is [O3] (in M to two decimal places) at equilibrium?
Ans: 5.78 * 10^-30 M
ozone can be created from oxygen gas (with an input of energy) via the following reaction:...
In the upper atmosphere, ozone is produced from oxygen gas in the following reaction. 3O2(g) → 2O3(g) Calculate ΔGo for this reaction. Enter your answer in kJ and give 3 significant figures. Calculate ΔHo for ozone formation. (Enter your answer in kJ and give 3 significant figures). Calculate ΔSo for ozone formation. (Enter your answer in J/K and give 3 significant figures). Assume an atmosphere where p(O2) = 0.120 atm, and where T = 298 K. Below what pressure of...
Calculate deltaG at 298K for the formation of one mole of ozone, O3, from oxygen gas, O2, when [O2]= 0.210 atm and [O3]= 5.00 x 10-7 atm. 3/2 O2 (g) ---> O3 (g) deltaHo= 143Kj, deltaSo= -.06868kJ/K the answer is 133 kJ/mol
Ozone (O3) in the atmosphere can be converted to oxygen gas by reaction with nitric oxide (NO). Nitrogen dioxide is also produced in the reaction. What is the enthalpy change when 8.50L of ozone at a pressure of 1.00 atm and 25°C reacts with 12.00 L of nitric oxide at the same initial pressure and temperature? [∆H°f (NO) = 90.4 kJ/mol; [∆H°f (NO2) = 33.85 kJ/mol; ∆H°f (O3)= 142.2 kJ/mol] [O3 + NO O2 + NO2] show all work...
Under certain conditions, oxygen will react to form ozone, as shown in the following equation: 3O2 (g) ⇌ 2O3 (g) Kp = 2.5 × 10-59 at 25°C. What ozone partial pressure is in equilibrium with oxygen in the atmosphere (Poxygen = 0.21 atm)?
Ozone decomposes to form oxygen molecules and oxygen atoms, O3(g) ? O2(g) + O(g), in the upper atmosphere. The energy of activation for this reaction is 93.1 kJ/mol. At 600 K, the rate constant for this reaction is 3.37
Ozone is formed from oxygen by the following reaction: 3/2 O2(g) ⇌ O3(g) Kp = 3.4 x 10-38 at 220 K. Calculate the value of Kc.
physical chemistry 2. The bond dissociation energy of oxygen gas is 495 kJ/mole, while the enthalpy of formation of ozone gas (O3(g))is 142.3 kJ/mole. For the reaction: NO +O3(g) NO2(g) + O2(g) it is found that AH = -198.9 kJ/mole, Determine the enthalpy change for the reaction: NO(g) + O() NO2(8)
A reaction of importance in the formation of smog is that between ozone and nitrogen monoxide described by O3(g)+NO(g)⟶O2(g)+NO2(g)O3(g)+NO(g)⟶O2(g)+NO2(g) The rate law for this reaction is rate of reaction=?[O3][NO]rate of reaction=k[O3][NO] Given that ?=3.02×106 M−1⋅s−1k=3.02×106 M−1⋅s−1 at a certain temperature, calculate the initial reaction rate when [O3O3] and [NONO] remain essentially constant at the values [O3]0=2.65×10−6 M[O3]0=2.65×10−6 M and [NO]0=7.57×10−5 M[NO]0=7.57×10−5 M, owing to continuous production from separate sources. Calculate the number of moles of NO2(g)NO2(g) produced per hour per...
Chapter 14 and 15 1) Ozone decomposes to oxygen gas. 20, (g) ---> 30, (9) A proposed mechanism for this decomposition is o, =====> 0, +O (fast, equilibrium) O, + ---> 20% (slow) What is the rate law derived from this mechanism? 2) N2(g) + 3 H2(g) — > 2 NH3(g) Kc = 11.60 at 600 °C. Calculate Kp for this reaction at this temperature. 3) The rate of a particular reaction doubles when the temperature is increased from 250...
The rate constant for the reaction of nitrogen monoxide and ozone as shown in the corresponding image, is 1.67 x 1010 M-1 s-1 at 325 K. The rate constant for the same reaction at 375 K is 2.79 x 1010 M-1 s-1 determine the activation energy of this reaction. A) 10.4 kJ B) 19.7 kJ C) 21.3 kJ D) 100.4 kJ O3(g) + NO(g) → O2(g) + NO2(g)