platypus foraging for prey can detect an electric field as small as 0.002 N/C To give...
Homework Answers
Magnitude of electric field due to point charge q (C) at distance r (m) from it ,
E = kq/r^2 N/C
Where k = 9×10^9 N m^2/C^2
Hence for E = 0.002 N/C and q = 20 nC = 20×10^-9 C, we get
0.002 = 9×10^9 * 20×10^-9 / r^2
r = 300 m
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platypus foraging for prey can detect an electric field as small as
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