Tom exerts a 250 N force on the shot at an angle of 75° above horizontal....
Tom exerts a 250 N force on the shot at an angle of 75° above horizontal. The mass of the shot is 7 kg. How big is the resultant force? What is the angle of this resultant force with respect to horizontal?
Homework Answers
Gravitational force on shot = mg = 7*9.8 = 68.8 N
Angle between two forces = 90+75 = 165 degree
Resultant = sqrt(250^2+68.8^2+2*250*68.8*cos 165 degree)
= 184.4 N answer
Angle with horizontal = arctan((250*sin 75 degree - 68.8)/(250 cos 75 degree))
= 69.46 degree above horizontal
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