The change in Hrxn for the reaction C8H8 + 10 O2 = 8 CO2 + 4 H2O is -4395 kJ/mol. Knowing this, as well as the standard enthalpies of formation below, calculate the standard enthalpy of formation of Styrene in kJ/mol.
change in Hf[CO2 (g)] = -393.5 kJ/mol
change in Hf[H2O (l)] = -285.8 kJ/mol
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help asap 3. Calculate the standard enthalpy change, Hº, for the following reaction using standard enthalpies of formation. (1 point) 2C2H2(g) + 502(g) → 4CO2(g) + 2H20(1) Standard Enthalpies of Formation AH for C2H2(g) = +226.7 kJ/mol AHfor CO2(g) = -393.5 kJ/mol AH for H2O(l) = -285.8 kJ/mol
The combustion reaction of ethane is as follows. C2H6(g) + 7/2 O2(g) → 2 CO2(g) + 3 H2O(l) Using Hess's law and the reaction enthalpies given below, find the change in enthalpy for this reaction. reaction (1): C(s) + O2(g) → CO2(g) ΔH = −393.5 kJ/mol reaction (2): H2(g) + 1/2 O2(g) → H2O(l) ΔH = −285.8 kJ/mol reaction (3): 2 C(s) + 3 H2(g) → C2H6(g) ΔH = −84.0 kJ/mol
When styrene C8H8 burns in oxygen to form carbon dioxide and liquid water under standard-state conditions at 25°C, 42.62 kJ are released per gram of styrene. Find the standard enthalpy of formation of styrene at 25°C. (Given: ΔH°f[CO2(g)] = –393.5 kJ/mol, ΔH°f[H2O(l)] = –285.8 kJ/mol)
Heat of Formation Calculations: 32) Use a standard enthalpies of formation (Ho) table to determine the change in enthalpy for each of these reactions Hrxn [n. Ho(products) - n. Ho(products)] CO (g): -110.5 kJ/mol; CO2 (g): -393.5 kJ/mol CH4 (g): -890.4 kJ/mol H2O (l): -285.8 kJ/mol; H2O (g): -241.8 kJ/mol H2S (g): -20.6 kJ/mol; NO: -90.2 kJ/mol NO2: +33.9 kJ/mol; HCl (g): -92.3 kJ/mol NaOH (s): -426.7 kJ/mol; SO2 (g): -296.8 kJ/mol a) CH4(g) + 2 O2(g) ---> CO2(g) +...
Calculate the standard enthalpy change for the fermentation process, in which glucose (C6H12O6) is converted into ethanol (C2H5OH) and carbon dioxide (CO2). Substance Enthalpy of Formation, CO2 (g) −393.5 kJ/mol CO2 (aq) −412.9 kJ/mol C2H5OH (l) −276.98 kJ/mol C6H12O6 (s) −1,274.5 kJ/mol H2O (g) −241.8 kJ/mol H2O (l) −285.8 kJ/mol O2 (g) 0 kJ/mol ______kJ/mol
Calculate the standard enthalpy change for the fermentation process, in which glucose (C6H12O6) is converted into ethanol (C2H5OH) and carbon dioxide (CO2). Substance Enthalpy of Formation, Δ H o f CO2 (g) −393.5 kJ/mol CO2 (aq) −412.9 kJ/mol C2H5OH (l) −276.98 kJ/mol C6H12O6 (s) −1,274.5 kJ/mol H2O (g) −241.8 kJ/mol H2O (l) −285.8 kJ/mol O2 (g) 0 kJ/mol
A.Using standard heats of formation, calculate the standard enthalpy change for the following reaction. N2(g) + 3H2(g) = 2NH3(g) B.Using standard heats of formation, calculate the standard enthalpy change for the following reaction. CaCO3(s) = CaO(s) + CO2(g) C. A scientist measures the standard enthalpy change for the following reaction to be -2910.6 kJ: 2C2H6(g) + 7 O2(g) = 4CO2(g) + 6 H2O(g) Based on this value and the standard enthalpies of formation for the other substances, the standard enthalpy...
Use the Data table to calculate ∆H for the reaction below:Reactions: Change in Enthalpy (∆H)(1) C (s) + O2 (g) -> CO2(g) ∆H1 = -393.5 kJ/ mol(2) H2 (g) + 1/2 O2 (g) -> H2O (l) ∆H2 = -285.8 kJ/mol(3) 2C2H6 (g) + 7O2 (g) -> 4 CO2 (g) + 6 H2O (l) ∆H3 = -283.0 kJ/molCalculate the enthalpy change for the reaction:2 C (s) + 3 H2 (g) -> C2H6(g) ∆H = ______________kJ/mol
A scientist measures the standard enthalpy change for the following reaction to be 2752.8 kJ : 6CO2(g) + 6H2O(1) C6H12O6 + 6 O2(g) Based on this value and the standard enthalpies of formation for the other substances, the standard enthalpy of formation of CH1:05 is kJ/mol A scientist measures the standard enthalpy change for the following reaction to be 53.9 LJ: CO2(g) + H2(g)— CO(g) + H2O() Based on this value and the standard enthalpies of formation for the other...
6. Hess's Law. Use the data in Table 1 to calculate AH for the reaction below: Table 1. Change in Enthalpy for Reactions Reactions Change in Enthalpy (AH) AH = -393.5 kJ/mol (1) C() (2) Hz((g) + + O2(g) O2(g) → CO2(8) → H2O(l) AH2 = -285.8 kJ/mol (3) 2CH.(g) + 702(g) → 4 CO2(g)+ 6H2O(1) AH = -283.0 kJ/mol Calculate the enthalpy change for the reaction: 2 C(s) + 3H2(g) → CzH6(g) AH = kJ/mol