the population standard deviation is 6.84 days, assuming a 95% confidence, what sample size would be required to obtain a margin of error of 2 days?
(Remember to round up to the nearest whole number for sample size.)
the population standard deviation is 6.84 days, assuming a 95% confidence, what sample size would be...
Refer to the Scheer Industries example in Section 8.2. Use 6.87 days as a planning value for the population standard deviation. a. Assuming 95% confidence, what sample size would be required to obtain a margin of error of 1.5 days (round up to the next whole number)? b. Assuming 90% confidence, what sample size would be required to obtain a margin of error of 2 days (round up to the next whole number)?
Assume that you want to construct a 95% confidence interval estimate of a population mean. Find an estimate of the sample size needed to obtain the specified margin of error for the 95% confidence interval. The sample standard deviation is given below. Margin of error =$5,standard deviation=$25 The required sample size is ????? (Round up to the nearest whole number as needed.)
Assume that you want to construct a 95% confidence interval estimate of a population mean. Find an estimate of the sample size needed to obtain the specified margin of error for the 95% confidence interval. The sample standard deviation is given below. Margin of error equals=$66, standard deviation equals=$2222 The required sample size is _____. (Round up to the nearest whole number as needed.)
Assume that you want to construct a 95% confidence interval estimate of a population mean. Find an estimate of the sample size needed to obtain the specified margin of error for the 95% confidence interval. The sample standard deviation is given below. Margin of errorequals $3, standard deviationequals $23 The required sample size is nothing . (Round up to the nearest whole number as needed.)
8.2.29 Question Help A manager wishes to estimate a population mean using a 95% confidence interval estimate that has a margin of error of +49.0. If the population standard deviation is thought to be 680, what is the required sample size? The sample size must be at least (Round up to the nearest whole number.)
Sheer industries is considering a new computer-assisted program to train maintenance employees to do machine repairs. In order to fully evaluate the program, the director of manufacturing requested an estimate of the population mean time required for maintenance employees to complete the computer assisted training. Use 8.74 days as a planning value for the population standard deviation. (Round your answers up to the nearest whole number.) (a) Assuming 95% confidence, what sample size would be required to obtain a margin...
A sample of size n=95 is drawn from a population whose standard deviation iso = 38. Part 1 of 2 (a) Find the margin of error for a 90% confidence interval for u. Round the answer to at least three decimal places. The margin of error for a 90% confidence interval for p is Part 2 of 2 (b) If the sample size were n = 62, would the margin of error be larger or smaller? (Choose one) , because...
Consider a population having a standard deviation equal to 9.96. We wish to estimate the mean of this population. (a) How large a random sample is needed to construct a 95% confidence interval for the mean of this population with a margin of error equal to 1? (Round your answer to the next whole number.) The random sample is units. (b) Suppose that we now take a random sample of the size we have determined in part a. If we...
A sample of size π=95 is drawn from a population whose standard deviation is σ=27. Part 1 of 2 (a) Find the margin of error for a 99% confidence interval for H. Round the answer to at least three decimal places. The margin of error for a 99% confidence interval for u is _______ . Part 2 of 2 (b) If the confidence level were 90%, would the margin of error be larger or smaller?
Assuming the population standard deviation = 2.6, at 95% confidence level, how large should a sample be to estimate the population mean with a margin of error not exceeding 0.25? Solve using R.