A roller coaster has mass 3000.0 kg and needs to make it safely through a vertical circular loop of radius 50.0 m.
What is the minimum angular momentum, in kg*m^2/s, of the coaster at the bottom of the loop to make it safely through? Neglect friction on the track. Take the coaster to be a point particle.
minimum velocity needed
v = sqrt ( 5 r g)
w = sqrt ( 5 rg) /r
now angular momentum at the instant
L = Iw
L = m r^2 sqrt ( 5 r g) / r
L = m r sqrt (5 r g)
L = 3000 x 50 sqrt(5 x 50 x 9.8) = 7.42 x 10^6 kg m^2/sec
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