At a given region in space, the electric field is E = 5.89 ✕ 103 N...
At a given region in space, the electric field is E = 5.89 ✕ 103 N C · m2 x2î. Note that when x is in m, E will be in N/C. Electric charges in this region are at rest. Determine the volume density of electric charge (in nC/m3) at x = 0.320 m. Suggestion: Apply Gauss's law to a box between x = 0.320 m and x = 0.320 m + dx. nC/m3
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At a given region in space, the electric field is E = 5.89 ✕ 103
N...
6. The electric field in the region of space shown is given by E (8i+2yj) N/C...
6. The electric field in the region of space shown is given by E (8i+2yj) N/C where y is in m. What is the magnitude of the electric flux through the top face of the cube shown? 2n 7. a a Charge of uniform linear density (4.0 nC/m) is distributed along the entire x axis. Determine the magnitude of the electric field on the y axis at y-2.5 m.
3.4 The electric field in a region of space is zero for x < 0 and...
3.4 The electric field in a region of space is zero for x < 0 and x 〉 9 m, and is Ezー-80 V/m for 0 〈 x 〈 3.0 m and is Ez +40 V/m for 3.0 〈 x 〈 9.0 m. (a) If the potential at zero for x 0 make a quantitative sketch of the electric potential for-1.0 〈 x 〈 10 m. (b) What distribution of charges produces the electric field? Hints: What type of charge...
An electric field in a given region of space is given by E=3.1x2i (in N/C). What...
An electric field in a given region of space is given by E=3.1x2i (in N/C). What is the magnitude of the potential difference between two points x=0 m and x=7.5 m, i.e. |V(x=7.5m)-V(x=0 m )|?
A region has a uniform electric field of 5.5 x 105 N/C pointing straight up. A...
A region has a uniform electric field of 5.5 x 105 N/C pointing straight up. A nickel that is initially uncharged is placed into this same region oriented horizontally. (The diameter of a nickel is 21 mm.) Being made of metal, the nickel will develop surface charges that cancel out the field in its interior (a) Find the charge density on each face of the nickel HC/m2 (b) Find the total charge on each face nc
An electric field in a given region of space is given by E-2.5x2i (in N/C). What...
An electric field in a given region of space is given by E-2.5x2i (in N/C). What is the magnitude of the potential difference between two points x=0 m and x=7.ל m, i.e. ÎV(x=7.7m)-V(xD m 提交答案 Tries 0/12
In a certain region of space, the charge density is given in cylindrical coordinates by the...
In a certain region of space, the charge density is given in cylindrical coordinates by the function p=20*r*e^(-r). Apply gauss's law to find D
In a region of space, the electric field varies according to E = (0.04 N/C) sin...
In a region of space, the electric field varies according to E = (0.04 N/C) sin 2000t, where t is in seconds. Find the maximum displacement current through a 1 m2 area perpendicular to Ē. A eBook
In a particular region of Earth's atmosphere, the electric field above Earth's surface has been measured...
In a particular region of Earth's atmosphere, the electric field above Earth's surface has been measured to bo 143 N/C downward at an altitude of 280 m and 16 NC downward at an altitude of 430 m. Calculate the volume charge density of the atmosphere, assuming it to be uniform between 280 and 430 m. (Hint: You may neglect the curvature of Earth. Why?) C/m3
Question 1 (compulsory): (i) State Gauss' law for the electric field (E-field) in words and explain its meaning. Write the corresponding mathematical expression and clearly define all symbols...
Question 1 (compulsory): (i) State Gauss' law for the electric field (E-field) in words and explain its meaning. Write the corresponding mathematical expression and clearly define all symbols and operations used. Describe one application of Gauss' law. 15% (ii) A very long wire carrying electric charge with uniform line charge density is located in free space. Applying Gauss' law, derive the E-field due to this wire. Clearly explain every step of your derivation and the assumptions you take. 40% Find...
When we applied Gauss's Law to find the electric field of an infinite sheet of charge,...
When we applied Gauss's Law to find the electric field of an infinite sheet of charge, we also treated the sheet as if it was very thin, like a sheet of paper. But if the sheet has an appreciable thickness, we can investigate the field within the sheet as well. Here are two views of a thick sheet of charge with my suggestion for a Gaussian surface, viewed both head-on and at an angle so you can see the distances:...
6. The electric field in the region of space shown is given by E (8i+2yj) N/C where y is in m. What is the magnitude of the electric flux through the top face of the cube shown? 2n 7. a a Charge of uniform linear density (4.0 nC/m) is distributed along the entire x axis. Determine the magnitude of the electric field on the y axis at y-2.5 m.
3.4 The electric field in a region of space is zero for x < 0 and x 〉 9 m, and is Ezー-80 V/m for 0 〈 x 〈 3.0 m and is Ez +40 V/m for 3.0 〈 x 〈 9.0 m. (a) If the potential at zero for x 0 make a quantitative sketch of the electric potential for-1.0 〈 x 〈 10 m. (b) What distribution of charges produces the electric field? Hints: What type of charge...
A region has a uniform electric field of 5.5 x 105 N/C pointing straight up. A nickel that is initially uncharged is placed into this same region oriented horizontally. (The diameter of a nickel is 21 mm.) Being made of metal, the nickel will develop surface charges that cancel out the field in its interior (a) Find the charge density on each face of the nickel HC/m2 (b) Find the total charge on each face nc
An electric field in a given region of space is given by E-2.5x2i (in N/C). What is the magnitude of the potential difference between two points x=0 m and x=7.ל m, i.e. ÎV(x=7.7m)-V(xD m 提交答案 Tries 0/12
In a region of space, the electric field varies according to E = (0.04 N/C) sin 2000t, where t is in seconds. Find the maximum displacement current through a 1 m2 area perpendicular to Ē. A eBook
In a particular region of Earth's atmosphere, the electric field above Earth's surface has been measured to bo 143 N/C downward at an altitude of 280 m and 16 NC downward at an altitude of 430 m. Calculate the volume charge density of the atmosphere, assuming it to be uniform between 280 and 430 m. (Hint: You may neglect the curvature of Earth. Why?) C/m3
Question 1 (compulsory): (i) State Gauss' law for the electric field (E-field) in words and explain its meaning. Write the corresponding mathematical expression and clearly define all symbols and operations used. Describe one application of Gauss' law. 15% (ii) A very long wire carrying electric charge with uniform line charge density is located in free space. Applying Gauss' law, derive the E-field due to this wire. Clearly explain every step of your derivation and the assumptions you take. 40% Find...
When we applied Gauss's Law to find the electric field of an infinite sheet of charge, we also treated the sheet as if it was very thin, like a sheet of paper. But if the sheet has an appreciable thickness, we can investigate the field within the sheet as well. Here are two views of a thick sheet of charge with my suggestion for a Gaussian surface, viewed both head-on and at an angle so you can see the distances:...
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