If 35.22 mL of NaOH solution completely neutralizes a solution containing 0.544 g of KHP, what...

Question

Question

If 35.22 mL of NaOH solution completely neutralizes a solution containing 0.544 g of KHP, what is the molarity of the NaOH solution?

Answer 1

Answer #1

The balanced equation is

KHP + NaOH -----> H₂O + NaKP

Number of moles of KHP = 0.544 g / 204.22 g/mol = 0.00266 mol

From the balanced equation we can say that

1 mole of KHP requires 1 mole of NaOH so

0.00266 mole of KHP will require

= 0.00266 mole of KHP *(1 mole of NaOH / 1 mole of KHP)

= 0.00266 mole of NaOH

molarity of NaOH = number of moles of NaOH / volume of solution in L

molarity of NaOH = 0.00266 mol / 0.03522 L = 0.0755 M

Therefore, the molarity of NaOH = 0.0755 M

Answer 2

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