Question

If 30.0 mL of NaOH solution is required to react completely with 0.43 g of KHC₈H₄O₄, what is the molarity of the NaOH solution?

Answer 1

KHCq Hq 0 g = 204022 gomoli Molar mass of So, 0.43 g of 4 0.43 g of KHC 9 440 4 KHC, H, 0 = 0.432 204-22 Jool = 0.002105572422 roll of KHC, 440 Na ĐH (4) + KH C, H,04 (44) + k NaCa 0,()-+ +,0 (1) NOW, ind of KHC, HOg heutralizes 1 mot of Nach So, 0.002105572422 mot of KHCA will neutralize 0.002105572422 mol of Me DHE Let, molality of Nadt solution - Swart So, 30.0mL of Sweet M Nadh = 30.0mk to Somerset molliti = 30 xS maua mmol = 30xSat x103nd 5 0.030 %S... mol Nagu 0.030 XSI 00 002105572422 Samor = 0.002105572422 = 0.070185 747 NOOL 0.030 . molarity of the Nooh solution, f. 20.00 , =0.070185747 M NOOV