Question

How much of a 3.56M NaOH solution would it take to completely react with 2.875 ml of a 1.32M MgCl, solution? What is the theoretical yteld of Mg(OH)2 (5) produced by this reaction?

Answer 1

A CH - C OCH₂ CH₂ + Näös CHz-C -OH t-OCH₂CH₂ H2O Chat OH + Ezt CH3 CH2oh ot Ethanol Acetic acid/ Ethanoic acid Ans NaOH react with MgCl2 to the reaction : Cl2 according 2NaOH + Mg cla Mg(OH)₂ + + 2Nace Sog Moles of Mg Cl in sol = 2.815 mlx 1.32 = 3.795 milimeler So, Moles of NaOH required =2x3.795 = 7.590 millimees

Thus, volume of required 3.56 M Naoh soln 7.59 x 10-3 moles 3.56 mol/L 20132x10-3 L -2.132 ml 3.795 mmoles Theoretically makes of Mq.com De formed So, Theoretical field of Mglona X 5 &glmal = 0.2201 grame 3.795 x 10-3 moles