Here:
M(Mg2+)=0.1 M
M(NaOH)=0.1 M
V(Mg2+)=0.8 L
According to balanced reaction:
2*number of mol of Mg2+ =1*number of mol of NaOH
2*M(Mg2+)*V(Mg2+) =1*M(NaOH)*V(NaOH)
2*0.1 M *0.8 L = 1*0.1M *V(NaOH)
V(NaOH) = 1.6 L
Answer: 1.6 L
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