Here:
M(Pb(NO3)2)=0.18 M
M(KI)=0.7 M
V(Pb(NO3)2)=2.1 L
According to balanced reaction:
2*number of mol of Pb(NO3)2 =1*number of mol of KI
2*M(Pb(NO3)2)*V(Pb(NO3)2) =1*M(KI)*V(KI)
2*0.18 M *2.1 L = 1*0.7M *V(KI)
V(KI) = 1.08 L
Answer: 1.1 L
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