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What is the pH of a solution that is .24 M K2HPO4 and .088 M K3PO4?

What is the pH of a solution that is .24 M K2HPO4 and .088 M K3PO4?

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Answer #1

mixture of K3PO4 and K2HPO4 act as acidic buffer

pH = pKa + log [K3PO4]/[K2HPO4]

pKa of K2HPO4 = 12.7

pH = 12.7 + log [0.088] / [0.240]

pH = 12.26

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What is the pH of a solution that is .24 M K2HPO4 and .088 M K3PO4?
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