Question

If you need 37.9 g of sulfur, how many grams of CaS2O3 are needed? Use factor label method.

Answer 1

Number of moles amount in g / molar mass

Number of moles of S= 37.9 g/32.065 g/ mole

=1.18 moles S

1 Mole CaS2O3 has 2 mole S

1.18 moles S* 1 Mole CaS2O3 / mole S

= 0.59 moles CaS2O3

Amount in g CaS2O3= number of moles * molar mass

= 0.59 moles CaS2O3*152.2062 g/ mole

= 89.8 g CaS2O3